Question.
Two blocks are in contact and pushing on one another. The blocks are on a frictionless surface. The mass of the blocks are 3.9kg and 9.9kg. The block with the mass of 3.9kg is being pushed into the 9.9kg block with a force of 69N. The 9.9kg block Is being pushed into the 3.3kg block with a force of 11N. What is the magnitude of the force exerted on the 3.9kg block by the 9.9kg block.
Answer.
Let R = force of action-reaction exerted by each block on the other.
Net force on block of mass 3.9 kg
= 69 - R N
and its acceleration will be
= (69 - R) / 3.9 m/s^2
Net force on block of mass 9.9 kg
= R - 11 N
and its acceleration will be
= (R - 11) / 9.9 m/s^2.
Both blocks will move with the same acceleration.
=> (69 - R) / 3.9 = (R - 11) / 9.9
=> R = 52.6 N.
Two blocks are in contact and pushing on one another. The blocks are on a frictionless surface. The mass of the blocks are 3.9kg and 9.9kg. The block with the mass of 3.9kg is being pushed into the 9.9kg block with a force of 69N. The 9.9kg block Is being pushed into the 3.3kg block with a force of 11N. What is the magnitude of the force exerted on the 3.9kg block by the 9.9kg block.
Answer.
Let R = force of action-reaction exerted by each block on the other.
Net force on block of mass 3.9 kg
= 69 - R N
and its acceleration will be
= (69 - R) / 3.9 m/s^2
Net force on block of mass 9.9 kg
= R - 11 N
and its acceleration will be
= (R - 11) / 9.9 m/s^2.
Both blocks will move with the same acceleration.
=> (69 - R) / 3.9 = (R - 11) / 9.9
=> R = 52.6 N.
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